The mean rotational kinetic energy of a diatomic molecule at temperature $T$ is

  • A
    $1/2 kT$
  • B
    $kT$
  • C
    $2kT$
  • D
    $5/2 kT$

Explore More

Similar Questions

$A$ polyatomic gas with $n$ degrees of freedom has a mean kinetic energy per molecule given by (if $K$ is Boltzmann's constant):

$A$ diatomic gas consisting of rigid molecules is at a temperature of $87^{\circ} C$. If the moment of inertia of the rotating diatomic rigid molecule is $2.76 \times 10^{-39} \text{ g cm}^2$,then the rms angular speed of the molecule is (Boltzmann constant $= 1.38 \times 10^{-23} \text{ J K}^{-1}$).

The degrees of freedom of a stationary rigid body rotating about its axis will be

The mean kinetic energy per degree of freedom of gas molecules is:

The ratio of specific heats of a gas is $\frac{9}{7}$. The number of degrees of freedom of the gas molecules for translational motion is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo